What is the weight of a 0.5mm thick magnets?

0.5mm thick magnet belongs to the ultra-thin magnets, mostly used in precision electronics, equipment, instruments, etc., some users want to know how much such a thin magnet, the following will be listed for you to calculate.

Calculation of the weight of 0.5mm thick magnets;

The weight of the magnet depends mainly on its volume and material density, calculated as weight = density × volume

5.5x0.7x0.5mm Small Thin Bar Magnets

Here is a 10x10x0.5mm square neodymium magnet as a case study, its volume is 10x10x0.5=50mm³, and the weight is calculated as 7.5g/cm³ x 50mm³ /1000 = 0.375g

Ring magnet volume calculations: V = π × height × (outer radius ² - inner radius ²)

To calculate the weight you need to multiply it by the density and divide by 4000.

Recommended Viewing Article; “How to calculate the weight of neodymium magnets? ”.

Density of several other common magnet materials:

Neodymium iron boron (NdFeB): about 7.5 g/cm³

Ferrite: approx. 5 g/cm³.

Aluminum-nickel-cobalt (AlNiCo): about 7.3 g/cm³

Samarium cobalt (SmCo): about 8.3 g/cm³

When the density is known, it can be calculated by substituting inside the formula.

Although magnets with 0.5mm thickness are light in weight (usually less than 1 gram), their application value should not be underestimated. By choosing suitable size and material, you can give full play to its performance and meet the needs of different fields. If you need ultra-thin magnets, we recommend contacting us for customized services.

Related magnet weight calculation articles;

How to calculate weight by knowing the size of ferrite ring magnets?